-2x^2=16x+30

Solution for -2x^2=16x+30 equation:

-2x^2=16x+30

We move all terms to the left:

-2x^2-(16x+30)=0

We get rid of parentheses

-2x^2-16x-30=0

a = -2; b = -16; c = -30;
Δ = b2-4ac
Δ = -162-4·(-2)·(-30)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4}{2*-2}=\frac{12}{-4}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4}{2*-2}=\frac{20}{-4}
=-5
$